What would you do?
A speedboat moving at 32.0 m / s approaches a no-wake buoy marker 100 meters ahead. The pilot slows the boat with a constant acceleration of -3.80 m/s2 by reducing the throttle. A) How much time does the boat to reach the buoy? answer in s (b) What is the speed of the boat when it reaches the buoy? answer in m / s
a) use dist vot = 1 / 2 a ^ 2 where V0 = initial velocity = 32m / s, t is time and an acceleration = – 3.8m/s/s have: 100 = 32m / s xt -1 / 2 3.8m/s/st ^ 2 or: 1.9T ^ 2-32t + 100 = 0, this quadratic has solutions: t = 4.14 and -12.7 s, since only the first sense, we know that it takes 4.14 seconds to reach the buoy V (t) = V0 + a V (4.14s) = 32m / S V -3.8m/s/sx 4.14s (4.14s) = 16.3 m / s
No Wake Zone Buoy, with CJ
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